Răspuns:
c
Explicație pas cu pas:
[tex]f\circ g = g\circ f \iff f(g(x)) = g(f(x)) \iff f(x+b) = g(ax+1)\iff a(x+b)+1 = (ax+1)+b\iff ax + ab + 1 = ax + 1 + b\iff ab + 1 = b + 1\iff ab = b\iff a = 1\\\\\textrm{b nu se poate afla.}\\\\f(x) = x+1\\\\g(x) = x + b[/tex]
