Răspuns:
Explicație pas cu pas:
-a+b=-1
a+b=5 2b=6 b=3 si a=2
f(x)=2x+3
f(x):R→R;
f(x)=ax+b;
A(-1, 1)∈Gf ⇒f(-1)=1;
-a+b=1;
B(1, 5)∈Gf ⇒f(1)=5;
a+b=5;
[tex]\left \{ {{-a+b=1;} \atop {a+b=5;}} \right. =>\left \{ {{-a+b=1;} \atop {a=5-b;}} \right. =>\left \{ {{-5+b+b-1=0;} \atop {a=5-b;}} \right. =>\left \{ {{b=3;} \atop {a=5-3=2;}} \right. \\\\=>f(x)=2x+3;[/tex]
