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Arătați că numărul 2(1+2+3....+2019)+2020 este pătratul perfect urgenttttttttttttt

Răspuns :

2(1+2+3....+2019)+2020=

=2×2019×2020÷2+2020

=2019×2020+2020

=2020(2019+1)

=2020×2020

=2020^2

Răspuns:

1+2+3+...+2019=(2019×2020)/2=2.039.190×2=4.078.380+2020=4.080.400

rad din 4.080.400=2020 (descompui in factori primi cu bara si ii scoti de sub radical)