[tex]f:\{0,1,2\}\rightarrow \{0,1,2,3,4,5\} \\ \\ f(0)+f(1)+f(2)\text{ este impar}\\ \\\text{Cazul (1) - f(0), f(1) si f(2) sa fie impare toate.} \\ \\ f(0)\rightarrow \text{3 cazuri posibile (1,3,5)} \\ f(1)\rightarrow \text{3 cazuri posibile (1,3,5)} \\ f(2)\rightarrow \text{3 cazuri posibile (1,3,5)}\\ \\ 3\cdot 3\cdot 3 = 27\\ \\ \text{Cazul (2) - f(0) par, f(1) impar, f(2) par}\\ \\ 3\cdot 3\cdot 3 = 27[/tex]
[tex]\text{Cazul (3) - f(0) impar, f(1) par, f(2) par}\\ \\ 3\cdot 3\cdot 3 = 27\\ \\ \text{Cazul (4) - f(0) impar, f(1) par, f(2) impar} \\ \\ 3\cdot 3\cdot 3 = 27\\ \\ \Rightarrow \text{Raspunsul este }4\cdot 27 = 108[/tex]
