Răspuns:
128/15•(1/5+4x/3-6x/5)•5/3•15/32 = 2^32/4^15
128/15•(3+20x-18x)/15•25/32 = 2^32/4^15
128/15•(3+2x)/3•5/32 = 2^32/4^15
[128•(3+2x)•5]/(15•3•32) = 2^32/4^15
2^7•(3+2x)/(2^5•3^2) = 2^32/4^15
2^2•(3+2x)/3^2 = 2^32/(2^2)^15
2^2•(3+2x)/3^2 = 2^2
3+2x=9
2x=6
x=3
