Răspuns:
7.f(x)=3x²+5x-2
V(-b/2a, -Δ/4a)
-b/2a= -(5/2*3)= -5/6
-Δ/4a= -(b²-4ac)/4a= -(5²-4*3*(-2))/4*3=
= -(25+24)/12= -49/12
V( -5/6;-49/12)
Revin imediat
8. f(x)=x²-5x+4
Intersectia cu Ox
f(x)=0
x²-5x+4=0
Δ=25-4*4=25-16=9
√Δ=√9=3
x1=(5-3)/2=1
X2=(5+3)/2=4
Punctele de intersectie
A(1,0) , B(4,0)
Intersectia cu OY
f(0)=o²-5*0+4=4
Intersectia cu Oy
C(0,4)
Revin imediat
9)f(x)=x²+mx+6
-Δ/4a= -(m²-4*6)/4=6
-(m²-24)=4*6
-m²+24=24
-m²=0
m=0
Explicație pas cu pas:
