Salut,
Ecuația devine:
[tex]\dfrac{5}{10}-\sqrt2x=\dfrac{6}{6}+\dfrac{5}{6}\Rightarrow\dfrac{1}{2}-\sqrt2x=\dfrac{11}{6}\\\\\dfrac{1}{2}-\dfrac{11}6=\sqrt2x\Rightarrow\dfrac{3}{6}-\dfrac{11}6=\sqrt2x\\\\-\dfrac{8}{6}=\sqrt2x\Rightarrow-\dfrac{4}{3}=\sqrt2x\Rightarrow x=-\dfrac{4}{\sqrt2\cdot 3}\\\\x=-\dfrac{4\cdot\sqrt2}{2\cdot 3},\ deci\ x=-\dfrac{2\cdot\sqrt2}{3}.[/tex]
Ai înțeles ?
Green eyes.
