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∆ABC dreptunghic in A ,AB =4 cm AC=3cm . BC=?​

Răspuns :

Folosim teorema lui Pitagora: BC² = AB²+AC² ⇒ BC = √(AB²+AC²)

BC = √(16+9)

BC = √25

BC = 5 cm

ABC dreptunghic in A si rezulta (T.Pitagora )

AB ^2+ AC ^2=BC^2

4^2+3^2=BC ^2

16+9=BC ^2

25=BC^2

5=BC