Răspuns:
a)f(2)=3+2
f(2)=5
b) Ox intersectat cu A(0;y)=> f(0)=3+0
f(0)=3=> A(0;3)
c)f(radical 2)=3+radical 2
f(-radica 2)=3-radical 2
f(radical 2) +f(- radical 2)=
3+radical 2 +3 - radical 3=
( radical 2 si - radical din 2 se elimina deoarece sunt numere opuse)
3+3=6
f(radical 2) +f( -radical 2) =6
