[tex]\it 1,25=\dfrac{\ 125^{(25}}{100}=\dfrac{5}{4}\\ \\ \\ 0,15=\dfrac{\ 15^{(5}}{100}=\dfrac{3}{20}\\ \\ \\ 0,1(6)=\dfrac{16-1}{90}=\dfrac{\ 15^{(15}}{90}=\dfrac{1}{6}[/tex]
Acum avem :
[tex]\it \dfrac{5}{4}\cdot\Big(\dfrac{^{3)}3}{\ 20}+\dfrac{^{10)}1}{\ \ 6}\Big)=\dfrac{5}{4}\cdot\dfrac{19}{60} =\dfrac{19}{4\cdot12}=\dfrac{19}{48}[/tex]
