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(x+1)la a doua - 1=?
(x-2la a doua - 9=?
X la a doua - (2x-1)la a doua=?



Răspuns :

[tex]( {x +1 )}^{2} - 1 = {x}^{2} + 2x + 1 - 1 = x ^{2} + 2x = x(x + 2) \\ ({x - 2)}^{2} - 9 = {x}^{2} - 4x + 4 - 9 = {x}^{2} - 4x - 5 \\ {x}^{2} - ( {2x - 1)}^{2} = {x}^{2} - 4 {x}^{2} + 4x - 1 = - 3 {x}^{2} + 4x - 1[/tex]