Un trapez dreptunghic ortodiagonal are h=media geometrică a bazelor.
[tex]\it h = \sqrt{18\cdot32} =\sqrt{9\cdot2\cdot32}=\sqrt{9\cdot64}=3\cdot8=24\ cm\\ \\ \mathcal{A}=\dfrac{\mathcal{B}+b}{2}\cdot h= \dfrac{32+18}{2}\cdot24=25\cdot24=600\ cm^2[/tex]