Răspuns:
Explicație
deduc gazul care se degaja, afland M din ecuatia de stare
pV= niuRT----> pV= mRT/M
0,44x1=0,504x0,082x(273+30)/M------> M=28,5g/mol====> N2
(NH4)2Cr207------> N2 + Cr2O3 + 4H2O
252g......................................152g
80g..................................x=.48,25g
p= m,px100/m,i= 48,25x100/60=80%
2N⁻³-6e---> 2N⁰
2Cr⁺⁶+6e--->2Cr⁺³