x^2 + 4x - 3x - 6x + 4 = x^2 - 8x + 16
-5x + 4 = -8x + 16
-5x + 8x = 16 - 4
3x = 12
x = 4
Răspuns:[tex]x^{2} +4x-3x-12-6x+4=x-16\\x^{2} -5x-8=x-16\\x^{2} -5x-8-x+16=0\\x^{2} -6x+8=0[/tex]
a=1 b=-6 c=8
Δ=b²-4ac=36-32=4
[tex]x1=\frac{-b-\sqrt{delta} }{{2a} }[/tex]
[tex]x1=\frac{6-2}{2} =\frac{4}{2} =2\\x2= \frac{-b+\sqrt{delta} }{2a} \\x2= \frac{6+2}{2} =\frac{8}{2} =4[/tex]
Δ=delta
Explicație pas cu pas:
