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O piramida triunghiulara regulata are volumul egal cu 3✓3 cm la a treia si inaltimea de 1 cm .Aflati latura bazei

Răspuns :

V = h × Ab /3

[tex] 3\sqrt{3} = \frac{1 \times \frac{ {l}^{2} \sqrt{3} }{4} }{3} [/tex]

[tex] \frac{ \frac{ {l}^{2} \times \sqrt{3} }{4} }{3} = 3 \sqrt{3} [/tex]

[tex] \frac{ {l}^{2} \times \sqrt{3} }{ 4} =9 \sqrt{3} [/tex]

[tex] {l}^{2} \times \sqrt{3} = 36 \sqrt{3} [/tex]

[tex] {l}^{2} = 36[/tex]

l = 6 cm ( latura bazei e 6 cm)