- se foloseste relatia :
n= m : M n=nr.moli ; m=masa subst. ; M =masa molara
m= n . M
a.
M NH3=1 4 + 3=17---------> 17g/moli
m=1mol . 17g/moli=17 g NH3
b.
MH2SO3=2+32 + 48=82------->82g/moli
m=0,1 moli .82g/moli=8,2 g H2SO3
c.
MCa(OH)2=40+ 32 +2=74--------> 74g/moli
m=0,01 moli. 74g/moli=0,74 g Ca(OH)2
d.
MNH4Cl=14 +4 +35,5=53,5------> 53,5g/moli
m=2000 moli . 53,5g/moli=107000 g=107 kg NH4Cl
e.
MZnS= 65 + 32=97--------> 97g/moli
m=97g/moli . 10000moli=970000 g =970 kg ZnS
II II
Zn S