1. calculam masa moleculara a substantei:
CO2
M(CO2) = 1x12+3x16 = 44 g/mol
2. in masa moleculara intelem ca
in 44 g CO2 ...............avem ..12 g C ... si ... 2x16g O
dar la 100% (100 g CO2) ... a% C ................ b% O
=: a = 12x100/44 = 27,27% C
b+ 32x100/44 = 72,73% O
deci 27,27% C + 72,73% O = 100% CO2
sper sa-ti fie pe inteles...
