concentratia molara se exprima prin numarul de moli de acid din 1l(1000ml) solutie
M,CH3COOH= 60g/mol
c=9%, inseamna ca in 1oog sol.sunt 9g otet
sau, din ro=m/v--> v=100g/1,011g/mol=98,9 ml
deci in 98,9ml sol...........9g otet
1000ml....................x=m=91g,CH3COOH
niu,CH3COOH= m/M= 91g/60g/mol=1,52mol----> c,m= 1,52M