Răspuns:
u=4√6
v=-2√3
a)|v|[tex]^{-1}[/tex] =(2√3)[tex]^{-1}[/tex]=[tex]\frac{1}{2\sqrt{3} }[/tex]=[tex]\frac{\sqrt{3} }{6}[/tex]
b) u·v=4√6·(-2√3)=-8√18=-24√2
c) u:v=[tex]\frac{4\sqrt{6} }{-2\sqrt{3} }[/tex]=-2√2
6.
a= [tex](\frac{2}{\sqrt{3} }-\frac{3}{2\sqrt{3}}+ \frac{1}{3\sqrt{3}}) :\frac{5}{\sqrt{3}}[/tex] =[tex](\frac{12}{6\sqrt{3}}-\frac{9}{6\sqrt{3}}+\frac{2}{6\sqrt{3}}):\frac{5}{\sqrt{3}}[/tex] = [tex]\frac{5}{6\sqrt{3}} :\frac{5}{\sqrt{3}}[/tex] = [tex]\frac{1}{6}[/tex]
=> [tex]a^{-1}[/tex]=6 ∈N
