fie a,b și c cele trei numere necunoscute
a+b+c=3560
a=60/100×b
c=30/100×a
c=30/100×60/100×b
60/100×b+b+30/100×60/100×b=3560
60b/100+b+3/10×6/10×b=3560
60b/100+b+18/100×b=3560
60b/100+b+18b/100=3560 (amplifica cu 100)
(Apoi împarte numitorul)
60b+100b+18b=35600
178b=356000
b=356000/178
b=2000
a=60/100×2000
a=12000/10
a=1200
c=30/100×1200
c=3600/10
c=360
VERIFICARE:2000+1200+360=3560
R:a=1200
b=2000
c=360
