a+b+c=49
b=7+a
c=11+b
a=? b=? c=?
Inlocuim b si c conform relatiilor:
a+7+a+11+7+a=49
3a+7+11+7=49
3a+7+11=49-7
=42
3a+7=42-11
=31
3a=31-7
=24
a=24:3
a=8
Aflam numarul b:
b=7+a
b=7+8
b=15
Aflam numarul c:
c=11+b
c=11+15
c=26
Verificare:
8+15+26=49
Raspuns:
a=8
b=15
c=26