Ecuația reacției chimice:
5 mmoli x
NaOH + HCl ------> NaCl + H₂O
1 1
Rezolvarea problemei:
[tex]V_s(NaOH)=10mL=0.01L\\C_M(NaOH)=0.5M\ (mol/L)\\\\C_M=\frac{n}{V_s}\implies n=C_M\ {\cdot}\ V_s=0.5\ mol/L\ {\cdot}\ 0.01\ L= 0.005 moli=5mmoli\ NaOH[/tex]
[tex]n_{HCl}=x=5\ mmoli=0.005\ moli\\C_M(HCl)=1M\ (mol/L)\\\\C_M=\frac{n}{V_s}\implies V_s=\frac{n}{C_M}=\frac{0.005\ moli}{1\ mol/L}=0.005\ L\ (dm^3)=5\ cm^3\ HCl[/tex]
