Răspuns:
f:R→R f(x)= lxl
f:(0,π/2]→(0.1] f(x)=cosx
f:[0.π/2]→[0,1] f(x)=sinx
f:[e.+∞)→[1,+∞)
f:[0.+∞)→[0+∞) f(x)=√x
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f:R→(-∞,0] f(x)= -lxl
f:(0,1)→(-∞,0) f(x)= lgx
f:(-π/2,0)→(0,1) f(x)=sin x
f:(π/2,π)→(-1,0) f(x)=cosx
f:(-∞ 0]→(-∞.0] f(x)=∛x
Explicație pas cu pas:
