se da: 0.1mol x-?
m(Fe₂O₃)=16g Fe₂O₃+3H₂=2Fe+3H₂O
m(H₂O)-? 1 mol 3mol
γ(H₂O)-? M(Fe₂O₃)=56*2+16*3=160g/mol
γ(Fe₂O₃)=m/M=16g/160g/mol=0,1mol
x=(H₂O)=γ(H₂O)=0.1mol*3mol/1mol=0,3mol
M(H₂O)=2+16=18g/mol
m(H₂O)=M*γ=18g/mol*0,3mol=5,4 g
b)se da: 0,1mol x-?
m(NaOH)=4g 2NaOH+H₂SO₄=Na₂SO₄+2H₂O
m(H₂O)-? 2 mol 2mol
γ(H₂O)-? M(NaOH)=23+1+16=40g/mol
γ(NaOH)=m/M=4/40=0,1mol
x= γ(H₂O)=0,1*2/2=0,1mol
M(H₂O)=2+16=18g/mol
m(H₂O)=M*γ=18g/mol*0,1mol=1,8 g
