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f:R->R
f(x)=ax+b
a.)f(-2)=-4
f(3)=6


Răspuns :

f(-2)=-2a+b=-4

f(3)=3a+b=6

3a+b-(-2a+b)=6-(-4)

5a=10

a=2

b=0

f(x)=2x