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determina compoziția procentuala a clururei de bariu ​

Răspuns :

BaCl2

-se afla masa moleculara

M=137+ 2. 35,5=208------>208g/moli

208gBaCl2-----------137 g Ba-----------71 g clor

100 g------------------------x------------------------y

x=100.137 :208=65,86 % Ba

y=100.71 :208=34,16 % clor