- se lucreaza in moli
xmoli ymoli 3moli
CaO + H2O = Ca(OH)2
1mol 1mol 1mol
x=3moli CaO
- se afla cantit. de CaO . Se aplica relatia :
n=m:M [ n=nr. moli ; m-masa subst. ( g ) ; M-masa molara ( g/moli ) ]
m=n.M
m=3moli . 56g/moli =168 g CaO
-se afla molii de H2O [ y ]
y=3moli H2O
-se afla cantit . de H2O
m=3moli .18g/moli = 54 g H2O
MCaO=40+16=56-----> 56g/moli
MH2O=2+ 16=18------> 18g/moli