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Scrie reactiile urmatoare sub forma ireductibilă, apoi aducetile la un mumitor comun:
6supra12 si 14 supra 21 ;5supra20 si 22supra55;9supra27si 9supra36;48supra60si 32supra56


Răspuns :

Răspuns:

Explicație pas cu pas:

1/2si2/3

1/4si2/5

1/3si1/4

4/5si4/7

Numitor comun

3/6si4/6

5/20si8/20

4/12si3/12

28/35si20/35

Răspuns:

Explicație pas cu pas:

6 / 12  si  14 / 21

6 / 12 = ( 6 : 6 ) / ( 12 : 6 ) = 1 / 2 → fractie ireductibila

14 / 21 = ( 14 : 7 ) / ( 21 : 7 ) = 2 / 3 → fractie ireductibila

→ c.m.m.m.c al numitorilor 2 si 3 = 2 × 3 = 6

1 / 2 = 3 / 6 → am amplificat fractia 1 / 2 cu 3

2 / 3 = ( 2× 2) / ( 3× 2 ) = 4 / 6

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5 / 20 si 22 / 55

5 / 20 = ( 5: 5) / ( 20 : 5) = 1 / 4

22 / 55 = ( 22 : 11 ) / ( 55 : 11 ) = 2 / 5

→ c.m.m.m.c al numitorilor 4 si 5 = 4× 5 = 20

1 / 4 = 5 / 20

2 / 5 = ( 2× 4) / ( 5 × 4) = 8 / 20

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9 / 27 si 9 / 36

9 / 27 = ( 9:9)/(27:9)= 1 / 3

9/36 = ( 9:9)/( 36:9) = 1 / 4

→ c.m.m.m.c al numitorilor celor 2 fractii ( 3; 4 ) = 12

1/3 = ( 1×4) / (3×4) = 4 / 12

1/4 = ( 1×3) / (4×3) = 3 / 12

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48 / 60   si   32 / 56

48 / 60 = ( 48 : 12 ) / ( 60:12) = 4 / 5 → fractie ireductibila

32 / 56 = ( 32:8)/ (56:8) = 4 / 7

→ cmmmc al numitorilor 5 si 7 = 5 × 7 = 35

→ amplific prima fractie ( 4 / 5 ) cu 7; iar farctia 4 / 7 cu 5

⇒  4 / 5 = ( 4×7) / ( 5×7) = 28/35

    4/7 = ( 4×5) / ( 7×5) = 20 / 35