Incepi in fiecare caz cu ultima relatie, deci in primul chenar o sa ai:
d=87+19=106
c+36=106
c=106-36=70;
b:3=70;
b=210;
a=210:2=105
In al doilea chenar:
d=294:6=49;
c=49*4=196;
b=c-29=196-29=167;
a=b+304=167+304=471.
In al treilea chenar:
e=19*6=114;
d=e:6=19;
c=d+13=19+13=22;
b=c*9=22*9=198;
a+b=300 => a=300-198=102.
In al patrulea chenar:
e=5*10=50;
d-e=250 => d=250+50=300;
c=d:10=300:10=30;
b=c*3=30*3=90;
a*b=90 => a=90:b=90:90=1.
