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Consideram funcția f:R->R, f(x) =3-2x. Calculati media geometrică a numerelor a=f(√2) si b=f(-√2)​

Răspuns :

[tex]f:\mathbb{R}\rightarrow\mathbb{R} \: \: \: ,f(x)=3-2x[/tex]

[tex]a = f( \sqrt{2} ) = 3 - 2 \sqrt{2} [/tex]

[tex]b = f( - \sqrt{2} ) = 3 - 2 \times ( - \sqrt{2} ) = 3 + 2 \sqrt{2} [/tex]

[tex]m_{g} = \sqrt{ab} [/tex]

[tex]m_{g} = \sqrt{(3 - 2 \sqrt{2} )(3 + 2 \sqrt{2} )} [/tex]

[tex]m_{g} = \sqrt{ {3}^{2} - {(2 \sqrt{2} )}^{2} } [/tex]

[tex]m_{g} = \sqrt{9 - 8} [/tex]

[tex]m_{g} = \sqrt{1} [/tex]

[tex]m_{g} = 1[/tex]