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A(2,-5) B(-7,3) C(1,4)
Ecuatia inaltimii din A in triunghiul ABC?


Răspuns :

[tex]A(2,-5),B(-7,3),C(1,4)[/tex]

[tex]Fie \: h_{A} \: inaltimea \: din \: A=>h_{A} \perp BC[/tex]

Panta lui BC :

[tex]m_{BC}=\frac{y_{C}-y_{B}}{x_{C}-x_{B}} = \frac{4 - 3}{4 - ( - 7)} = \frac{ 1}{4 + 7} = \frac{ 1}{11} [/tex]

[tex]h_{A}\perp BC=>m_{h_{A}}\times m_{BC}=-1[/tex]

[tex]m_{h_{A}} \times \frac{1}{11} = - 1[/tex]

[tex] \frac{1}{11} m_{h_{A}}= -1 = > m_{h_{A}} = -\frac{1}{ \frac{1}{11} } = -11[/tex]

[tex]h_{A}:y-y_{A}=m_{h_{A}}(x-x_{A})[/tex]

[tex]h_{A}:y - ( - 5) = -11(x - 2)[/tex]

[tex]h_{A}:y + 5 = -11x +22[/tex]

[tex]h_{A}:y = -11x + 22 - 5[/tex]

[tex]h_{A}: y= -11x + 17[/tex]