Răspuns:
5/3
Explicație pas cu pas:
Metoda 1:
[tex]5^{x-1}=\sqrt[3]{25}\\5^{x-1}=\sqrt[3]{5^2}\\5^{x-1}=5^{\frac{2}{3} } \\Functia~exponentiala~este ~injectiva.\\x-1=2/3x=1~+~2/3\\x=(3+2)/3\\x=5/3\\[/tex]
Metoda 2:
[tex]5^{x-1}=\sqrt[3]{25}\\ Ridicam~la~puterea~a~treia.\\(5^{x-1})^3=25\\5^{3x-3}=5^2\\Functia~ exponentiala~ este ~injectiva.\\3x-3=2\\3x=5\\x=5/3[/tex]
