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K=20N/m. , Ep=14,4 J , x=?​
imi trebuie urgent pana la 10..


Răspuns :

Ep=K*x²/2

x²=2Ep/K

=2*14,4/20=1,44m

x=1,2m

Aici este vorba de energie potentiala de tip elastic , are formula Ep=kx²/2 , de unde scoatem x, x=√(2Ep/k)=√(2*14,4/20)=√(28,8/20)=√1,44=1,2 m=120 cm