Avem v, Ec=Ep/2 .
Se cere h la care energia cinetica este jumatate din energia potentiala.
[tex]E_{mi} =E_{c} +E_{p}[/tex]
[tex]E_{mi} =\frac{mv_0^{2} }{2}[/tex]
=>[tex]\frac{mv_0^{2} }{2} =E_{c} +E_{p}[/tex]
Dar Ec=Ep/2 =>
[tex]\frac{mv_o^{2} }{2} =\frac{Ep}{2} +Ep \\Aducem la acelasi numitor si obtinem\\ \\mv_0^{2} =3Ep\\mv_0^{2} =3mgh \\\\ h=\frac{v_0^{2} }{3g}[/tex]
