[tex]\it \dfrac{5x+3}{x+2}\in\mathbb{Z} \Rightarrow x+2|5x+3\ \ \ \ (1)\\ \\ \\ Dar\ x+2|x+2 \Rightarrow x+2|(x+2)\cdot5 \Rightarrow x+2|5x+10\ \ \ \ (2)\\ \\ \\ (1),(2) \Rightarrow x+2|5x+10-5x-3 \Rightarrow x+2|7 \Rightarrow x+2\in D_7 \Rightarrow\\ \\ \\ \Rightarrow x+2\in \{-7,\ -1\ ,1,\ 7\}|_{-2} \Rightarrow x\in\{-9,\ -3,\ -1,\ 5\}[/tex]