1)
[tex]\it subunitare:\ \dfrac{3}{5},\ \ \dfrac{2^3}{3^2}=\dfrac{8}{9}\\ \\ \\ echiunitare:\ \dfrac{10}{10},\ \ \dfrac{\ 2^4}{16}=\dfrac{16}{16}[/tex]
[tex]\it 8b)\ \ \dfrac{1}{15}+\dfrac{2}{15}+\dfrac{3}{15}+\ ...\ +\dfrac{29}{15}=\dfrac{1+2+3+\ ...\ +29}{15}=\dfrac{\dfrac{29\cdot30}{2}}{15}=\\ \\ \\ =\dfrac{29\cdot15^{(15}}{15}=29[/tex]
