Notatii:
Cele 4 nr nat a,b,c,d
a+b+c+d=2021
Din teorema impartirii cu rest avem:
a=2b+1
b=2c+1
c=2d+1
a+b+c+d=2021
2b+1+2c+1+2d+1+d=2021
4c+2+4d+2+3d+3=2021
8d+4+7d+7=2021
15d+11=2021 |-11
15d=2010 |:15
d=134
=>c=134×2+1=268+1=269
=>b=269×2+1=538+1=539
=>a=539×2+1=1078+1=1079
Sper ca te am ajutat!
