Vs = 1 L = 1000 ml
ro = p = 0,79 g/ml
p = ms/Vs => ms = pxVs = 0,79x1000 = 790 g sol etanol
w% = 96% = mdx100/ms
=> md = msxw%/100 = 790x96/100 = 758,4 g etanol dizolvat
=> ms.final = ms + m.apa = 790 + 1972 = 2762 g sol. totala
md = a ramas aceeasi = 758,4 g
=> w%.final = mdx100/ms.final = 758,4x100/2762 = 27,5%
