Mg (A=24, Z=12)
a. 12p+ , 12e- , 12n0
b. neutra
c. 24 g Mg ....... 12x6,022x10^23 p+
0,6 g Mg ............. n = 1,807x10^23 p+
d. 1s2 2s2 2p6 3s2
e. 1 mol Mg avem 6x6,022x10^23 e- tip s
la 0,5 moli ................ n = 18,066x10^23 = 1,807x10^24 e- tip s
f. 24 g Mg contin ............. 6x6,022x10^23 e- tip p
a g ..................................... 3,011x10^20 e- tip p
=> a = 0,002 g Mg
