se aplica regula dreptunghiului.....
c1 = 60% -------------------------> diagonala: 30-20 = 10 parti sol. c1=60%
l l
l c3 = 30% l
l l
c2 = 20% --------------------------> diagonala: 60-30 = 30 parti sol. c2=20%
total = 10+30 = 40 parti sol. c3=30%
ms3 = pxVs = 1,152x5000 = 5760 g sol.
daca la 40 parti sol. c3 .... 10 p. sol. 60% ....... 30 p. sol. 20%
la 5760 g sol. c3 ................ a g sol. 60% ............. b g sol. 20%
=> a = 1440 g sol. 60%
=> b = 4320 g sol. 20%
