Răspuns
Explicație pas cu pas:
[tex]\frac{2^{38}\times 3^{40} + 6^{38}-9^{19}\times 4^{20}}{3^{20}\times 4^{20}-12^{19}} =[/tex]
[tex]\frac{3^2\times (2\times3)^{38} + 6^{38}-3^{19\times2}\times 2^{20\times2}}{12^{20}-12^{19}} =[/tex]
[tex]\frac{6\times (6)^{38} + 6^{38}-4\times3^{38}\times 2^{38}}{12^{19}(12-1)} =[/tex]
[tex]\frac{6^{38}\times(6+1-4)}{12^{19}(11)} =\frac{6^{38}\times3}{12^{19}\times11} =\frac{6^{38}\times3}{6^{19}\times2^{19}\times11}=\frac{6^{19}\times3}{2^{19}\times11}=\frac{3^{19}\times3}{11}=\frac{3^{20}}{11}[/tex]