1 mol-atomi contine 6,022x10^23 atomi, conform legii lui Avogadro
a)
1 mol-atomi Ag ............... 6,022x10^23 atomi Ag
n moli................................ 12,044•10^24 atomi Ag
=> n = 12,044•10^24 / 6,022x10^23 = 20 moli Ag
b)
1 mol K cantareste 39 g (masa atomica A = 39)
1 mol K ................. 39 g K
n moli K ................. 78 g K
=> n = 78x1/39 = 2 moli K
c)
1 mol C cantareste 12 g (vezi masa atomica A = 12)
1 mol C ................. 12 g C
n moli ................... 3600 g C
=> n = 3600x1/12 = 300 moli C
