M,AgCl= 143,5g/mol
M,AgNO3=170g/mol
NaNo3 nu reactioneaza cu HCl
amestecul de nitrati contine: 40/100X10=4gNaNO3
60/100x10=6gAgNO3
1mol..................................1mol sau, in grame
AgNO3 + HCl-----> AgCl↓ + HNO3
170g...............................143,5g
6g.....................................x= m,AgCl= 6x143,5/170=.........calculeaza