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Scoateți factorii de sub radical din:9610;6760;4375;3087;4732;2268.
va rog ajutați.ma,este urgent!!dau coroană!


Răspuns :

[tex]a) \sqrt{9610} = \sqrt{2 \times 5 \times 31 \times 31} = \sqrt{(31 \times 31) \times 2 \times 5} = \sqrt{ {31}^{2} \times 2 \times 5 } = 31 \sqrt{2 \times 5} = 31 \sqrt{10} [/tex]

[tex]b) \sqrt{6760} = \sqrt{2 \times 2 \times 2 \times 5 \times 13 \times 13} = \sqrt{(2 \times 2) \times (13 \times 13) \times 2 \times 5} = \sqrt{ {2}^{2} \times {13}^{2} \times 2 \times 5 } = (2 \times 13) \sqrt{2 \times 5} = 26 \sqrt{10} [/tex]

[tex]c) \sqrt{4375} = \sqrt{5 \times 5 \times 5 \times 5 \times 7} = \sqrt{(5 \times 5) \times (5 \times 5) \times 7} = \sqrt{ {5}^{2} \times {5}^{2} \times 7 } = (5 \times 5) \sqrt{7} = 25 \sqrt{7} [/tex]

[tex]d) \sqrt{3087} = \sqrt{3 \times 3 \times 7 \times 7 \times 7} = \sqrt{(3 \times 3) \times (7 \times 7) \times 7} = \sqrt{ {3}^{2} \times {7}^{2} \times 7 } = (3 \times 7) \sqrt{7} = 21 \sqrt{7} [/tex]

[tex]e) \sqrt{4732} = \sqrt{2
\times 2 \times 7 \times 13 \times 13} = \sqrt{(2 \times 2) \times (13 \times 13) \times 7} = \sqrt{ {2}^{2} \times {13}^{2} \times 7 } = (2 \times 13) \sqrt{7} = 26 \sqrt{7} [/tex]

[tex]f) \sqrt{2268} = \sqrt{2 \times 2 \times 3 \times 3 \times 3 \times 3 \times 7} = \sqrt{(2 \times 2) \times (3 \times 3) \times (3 \times 3) \times 7} = \sqrt{ {2}^{2} \times {3}^{2} \times {3}^{2} \times 7 } = (2 \times 3 \times 3) \sqrt{7} = 18 \sqrt{7} [/tex]