m,NaCl pur= pxm,i/100g=80x234/100g=187,2g
niu,NaCl= m/M= 187,2/58,5mol=3,2mol
NaCl------> Na⁺+ Cl⁻
catod(-): Na⁺+e---> Na
anod (+): CL⁻+e---> Cl; Cl +Cl=> Cl2
2NaCl---> 2Na + Cll2
2mol...........2mol
3,2mol........x= 3,2molNa
m,Na=niuxM=3,2molx23g/mol= .......................calculeaza !!!!