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fie ,
[tex]f(x) = {3x}^{2} - 3x + 1[/tex]
si
[tex]g(x) = x - 1.[/tex]
determinati solutiile reale ale ecuatiei f(x)= -g(x)


Răspuns :

f(x)=-g(x)<=>3x²-3x+1=-(x-1)<=>3x²-3x+1=-x+1<=>3x²-2x=0<=>x(3x-2)=0=>x₁=0 si x₂=2/3

S={0;2/3}

3x^2 - 3x + 1 = -x + 1
3x^2 - 2x = 0
x(3x - 2)=0
x1=0
x2=2/3