1. CnH2nO2 d=M/M,O2----> M= 1,457x32=> 46g/mol
14n+32= 46---> n=1-> acidul formic HCOOH
c,m= niu/V----> niu,NaOH= 2x0,2mol=0,4molNaOH
HCOOH+NaOH---> HCOONa+H2O
----> din aceasta ecuatie, rezulta 0,4mol acid--> c= 0,4/0,1=> 4M
2. a molHCOOH + b mol CH3COOH
M,ac.formic=46g/mol, M,ac.aetic= 60g/mol
m,amestec= 46a + 60b= 15,2g...........................................ecuatia 1
niu=2x0,15 mol= 0,3mol NaOH
HCOOH + NaOH---> HCOONa+H2O...................ori a
CH3COOH+NaOH---> CH3COOH +H2O.............ori b
a+b=0,3..........................................................................................ecuatia 2
din cele doua ecuatii, rezulta : a= 0,1mol b= 0,2mol-->raportul molar= 1/2