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2*4+2*3×[(2*16)totul la a5:2*77+2×2*55:2*53]:4*3

Răspuns :

Răspuns: [tex]\bf \red{\underline{~18~}}[/tex]

Explicație pas cu pas:

[tex]\bf 2^4+2^3\cdot\Big[\big(2^{16}\big)^5:2^{77}+2\cdot2^{55}:2^{53}\Big]:4^3=[/tex]

[tex]\bf 2^4+2^3\cdot\Big(2^{16\cdot5}:2^{77}+2^{1+55-53}\Big):\big(2^2\big)^3=[/tex]

[tex]\bf 2^4+2^3\cdot\Big(2^{80}:2^{77}+2^{3}\Big):2^{2\cdot 3}=[/tex]

[tex]\bf 2^4+2^3\cdot\Big(2^{80-77}+2^{3}\Big):2^{6}=[/tex]

[tex]\bf 2^4+2^3\cdot\Big(2^{3}+2^{3}\Big):2^{6}=[/tex]

[tex]\bf 2^4+2^3\cdot2^3\cdot\Big(2^{3-3}+2^{3-3}\Big):2^{6}=[/tex]

[tex]\bf 2^4+2^3\cdot2^3\cdot\Big(2^{0}+2^{0}\Big):2^{6}=[/tex]

[tex]\bf 2^4+2^{6}\cdot\big(1+1\big):2^{6}=[/tex]

[tex]\bf 2^4+2^{6}\cdot2:2^{6}=[/tex]

[tex]\bf 2^4+2^{6+1-6}=2^4+2^{1}=[/tex]

[tex]\bf 16 + 2 =\red{\underline{~18~}}[/tex]

[tex]==pav38==[/tex]