vom nota cu dT = delta T
a)
3 = transf. izocora
=> dU = niuxCvxdT
gaz monoatomic => Cv = 3R/2
=> dU = 3x3x8,31xdT/2 = 38dT
b)
Q3--->1 = izobara
U = niuxCpxdT
Cp = 5R/2
=> U = 3x5x8,31xdT/2 = 62,33dT
c)
Q1-->2 = izoterma
U = 0
d)
L.tot = L1-2 + L2-3 + L3-1
= niuRdTln(V2/V1) + 0 + niuRdT
= 0 + 0 + 3x8,31xdT
=> L.tot ≅ 25dT
Cred ca lipseste temperatura din datele problemei..... !!!