Ex 3 va roggg!Imi trebuie urgent pana la o anumită ora!Dau coroana

[tex]\it a)\ AO - mediana\ ipotenuzei \Rightarrow AO=\dfrac{BC}{2} \Rightarrow AO=OC \Rightarrow \Delta AOC\ -\ isoscel[/tex]
[tex]\it b)\ \Delta AOC-\ isoscel\ ( AO=OC)\ \Rightarrow \widehat{OAC} =\widehat{OCA}=15^o\\ \\ \widehat{AOB}=15^o+15^o=30^o\ \ (unghi\ exterior\ pentru\ \Delta AOC)[/tex]
[tex]\it c)\ \ T.\ \measuredangle\ 30^o\ \hat\imath n\ \Delta BDO \Rightarrow OB=2\cdot8=16\ cm\\ \\ BC=2\cdot16=32\ cm[/tex]